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qtech系列故事之——11.11

📝 题解 🔵 仅限 C++
题目描述
<p class="p0" style="text-indent:24.0000pt;"> 传说中的<span>11</span><span>月</span><span>11</span><span>日!想必你也知道是什么日子吧!就是大名鼎鼎的光棍节啦!</span><span>qtech</span><span>的</span><span>ACMer</span><span>们,绝大部分人自然也中枪了!但是,有一个很古老的传说!就是说,在</span><span>11</span><span>月</span><span>11</span><span>日这天,如果你还是光棍!那么你就刷</span><span>11</span><span>道题!来年一定会脱光的!(脱离光棍,大家不要误解)</span> </p> <p class="p0" style="text-indent:24.0000pt;"> 671coder<span>是</span><span>qtech</span><span>的一名弱菜,他听信了这个古老的传说!于是他打开的</span><span>qtech</span><span>的</span><span>OJ</span><span>,找到了当天的</span><span>judge&nbsp;status</span><span>,他想知道明年这个时候谁可以脱光!</span> </p> <p class="p0" style="text-indent:24.0000pt;"> (<span>judge&nbsp;status</span><span>有很多种,当然不是每次都会</span><span>ac</span><span>的哦!可能会出现的结果有:</span><span>wa</span><span>、</span><span>tle</span><span>、</span><span>re</span><span>、</span><span>ce</span><span>、</span><span>pe</span><span>、</span><span>ole</span><span>、</span><span>mle</span><span>……</span><span>Author</span><span>之间可以保证是没有空格的)</span> </p> <p class="p0"> &nbsp; </p> <p class="p0"> Input </p> <p class="p0"> &nbsp; </p> <p class="p0" style="text-indent:24.0000pt;"> 首先输入一个数<span>n</span><span>,代表有</span><span>11</span><span>月</span><span>11</span><span>日这天有</span><span>n</span><span>个提交的</span><span>judge</span><span>。</span><span>(n&lt;=30)</span> </p> <p class="p0" style="text-indent:24.0000pt;"> 接着跟着<span>n</span><span>行,每行有</span><span>4</span><span>个元素组成,第一个是</span><span>Author</span><span>,第二个是</span><span>Problem&nbsp;ID</span><span>,第三个是</span><span>time</span><span>,第四个是</span><span>judge&nbsp;status</span><span>。要注意的是:有人为了骗脱光,可能会同一题目</span><span>AC</span><span>好几次。其实这也是不算的。还有的想在</span><span>24</span><span>点之前结束提交,但是不慎到了第二天的</span><span>0</span><span>点多才</span><span>ac</span><span>,这些都是不计算的。(请注意有多组测试数据)</span> </p>
输入格式
<p class="p0" style="text-indent:21.0000pt;"> <br /> </p> <p class="p0" style="text-indent:24.0000pt;"> 首先输入一个数<span>n</span><span>,代表有</span><span>11</span><span>月</span><span>11</span><span>日这天有</span><span>n</span><span>个提交的</span><span>judge</span><span>。</span><span>(n&lt;=30)</span> </p> <p class="p0" style="text-indent:24.0000pt;"> 接着跟着<span>n</span><span>行,每行有</span><span>4</span><span>个元素组成,第一个是</span><span>Author</span><span>,第二个是</span><span>Problem&nbsp;ID</span><span>,第三个是</span><span>time</span><span>,第四个是</span><span>judge&nbsp;status</span><span>。要注意的是:有人为了骗脱光,可能会同一题目</span><span>AC</span><span>好几次。其实这也是不算的。还有的想在</span><span>24</span><span>点之前结束提交,但是不慎到了第二天的</span><span>0</span><span>点多才</span><span>ac</span><span>,这些都是不计算的。(请注意有多组测试数据)</span> </p> <span></span> <p> <br /> </p>
输出格式
<p class="p0" style="text-indent:21.0000pt;"> 输出来年可以脱光的<span>Author</span><span>,如果没有人脱光,那么则输出</span>”NULL”。如果有多个人脱光,谁先<span>ac11</span><span>道题就先输出谁。(可以保证测试数据的输入是么按照实际顺序输入的,如果有同时</span><span>ac11</span><span>道题的,先输入的</span><span>Author</span><span>先输出)</span> </p>
样例
样例输入 1
29 671coder 1001 2013-11-11 05:30:07 Accepted 671coder 1002 2013-11-11 05:30:08 Accepted 671coder 1003 2013-11-11 05:30:09 Accepted xindoo 1001 2013-11-11 11:00:00 Wrong Answer xindoo 1001 2013-11-11 11:00:01 Time Limit Exceeded xindoo 1002 2013-11-11 11:00:02 Runtime Error 671coder 1004 2013-11-11 11:30:10 Accepted 671coder 1005 2013-11-11 11:30:11 Accepted 671coder 1006 2013-11-11 11:30:12 Accepted xindoo 1001 2013-11-11 12:00:03 Compilation Error xindoo 1002 2013-11-11 12:00:04 Output Limit Exceeded xindoo 1001 2013-11-11 12:00:05 Presentation Error xindoo 1002 2013-11-11 12:00:06 Wrong Answer 671coder 1007 2013-11-11 15:30:08 Accepted 671coder 1008 2013-11-11 15:30:09 Accepted 671coder 1009 2013-11-11 15:30:10 Accepted xindoo 1001 2013-11-11 15:30:10 Accepted xindoo 1002 2013-11-11 15:30:11 Accepted xindoo 1003 2013-11-11 15:30:12 Accepted xindoo 1004 2013-11-11 15:30:13 Accepted xindoo 1005 2013-11-11 15:30:14 Accepted xindoo 1006 2013-11-11 15:30:15 Accepted xindoo 1007 2013-11-11 15:30:16 Accepted xindoo 1008 2013-11-11 15:30:17 Accepted xindoo 1009 2013-11-11 15:30:18 Accepted xindoo 1010 2013-11-11 15:30:19 Accepted 671coder 1010 2013-11-11 23:59:58 Accepted 671coder 1011 2013-11-11 23:59:59 Accepted xindoo 1011 2013-11-12 00:00:01 Accepted
样例输出 1
671coder
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